28x^2+60=-152x

Solution for 28x^2+60=-152x equation:

28x^2+60=-152x

We move all terms to the left:

28x^2+60-(-152x)=0

We get rid of parentheses

28x^2+152x+60=0

a = 28; b = 152; c = +60;
Δ = b2-4ac
Δ = 1522-4·28·60
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(152)-128}{2*28}=\frac{-280}{56}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(152)+128}{2*28}=\frac{-24}{56}
=-3/7
$